14x^2+19x^2-3x=0

Solution for 14x^2+19x^2-3x=0 equation:

14x^2+19x^2-3x=0

We add all the numbers together, and all the variables

33x^2-3x=0

a = 33; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·33·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*33}=\frac{0}{66}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*33}=\frac{6}{66}
=1/11
$